Computer Networking : A Top-Down Approach

Computer Networking : A Top-down Approach

Authors: James F. Kurose, Keith W. Ross
ISBN: 9780132856201
Edition: 6
Chapter: Computer Networks And The Internet
Exercise: Problems
Question: 6

 

Question by Anonymous on 12 Oct, 2017 at 05:23 AM

This elementary problem begins to explore propagation delay and transmission delay, two central concepts in data networking. Consider two hosts, A and B, connected by a single link of rate R bps. Suppose that the two hosts are separated by m meters, and suppose the propagation speed along the link is s meters/sec. Host A is to send a packet of size L bits to Host B.

a. Express the propagation delay, dprop, in terms of m and s.

b. Determine the transmission time of the packet, dtrans, in terms of L

and R.

c. Ignoring processing and queuing delays, obtain an expression for the end-to-end delay.

d. Suppose Host A begins to transmit the packet at time t = 0. At time t = dtrans,where is the last bit of the packet?

e. Suppose dprop is greater than dtrans. At time t = dtrans, where is the first bit of the packet?

f. Suppose dprop is less than dtrans. At time t = dtrans, where is the first bit of the packet?

g. Suppose s = 2.5 · 108, L = 120 bits, and R = 56 kbps. Find the distance m so that dprop equals dtrans.

Answer by Geroge on 12 Oct, 2017 at 05:23 AM

a) The propagation delay, dprop=m/s sec

b) The transmission time of the packet, dtrans=L/R sec

c)  The end-to-end delay=(L/R+m/s) sec

d) Suppose Host A begins to transmit the packet at time = 0. At time dtrans.

Then, the last bi of the packet dtrans

e) Suppose dprop is greater than dtrans. At time dtrans

Thus, the first bit of the packet is dpropdtrans.

f)Suppose dprop is less than dtrans. At time dtrans,

Thus, the first bit of the packet is dpropdtrans.

0 0

Discussions

Vamshi Banoth on 07 Oct, 2018 at 09:42 AM


answers for:

d)The bit is just leaving Host A

e)The first bit is in the link and has not reached Host B

f)The first bit has reached Host B

 

Post the discussion improve the above solution.