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Computer Networking : A Top-Down Approach

Computer Networking : A Top-down Approach

Authors:
James F. Kurose, Keith W. Ross
Exercise:
Problems
Chapter:
Computer Networks And The Internet
Edition:
6
ISBN:
9780132856201
Question:
12

 

Question

A packet switch receives a packet and determines the outbound link to which

the packet should be forwarded. When the packet arrives, one other packet is halfway done being transmitted on this outbound link and four other packets are waiting to be transmitted. Packets are transmitted in order of arrival.

Suppose all packets are 1,500 bytes and the link rate is 2 Mbps. What is the queuing delay for the packet? More generally, what is the queuing delay when all packets have length L, the transmission rate is R, x bits of the currently-being-transmitted packet have been transmitted, and n packets are already in the queue?

Answer

Consider the given data:

0 0

Discussions

Geroge

Given data:
L=Length of packet=1500 bytes
R=Rate of transmission =2Mbps 
x=Current transmit packet=L/R=1500/2=750
n=Waiting queue=4
Queuing delay=(nL+(L-x))/R
                          =(4*1500)(1500-750)/2
                         =6750/2
                         =3375 Mbps
                         =0.033 seconds

Anon

The value 0.027 seconds is correct but the method is unclear. The other comment provides the correct formula but mixes up units.

 

L (packet length) = 1500 bytes

R (transmission rate) = 2 Mbps

x (currently transmitting packet) = L / 2 = 750 bytes

n (number in queue) = 4 packets

Queuing Delay = (nL + (L – x)) / R

 

(nL + (L – x)) / R = (4 * 1500 + (1500 – 750)) bytes / 2 Mbps

= 6570 bytes / 2 Mbps

= 0.027 Mb / 1 Mbps

= 0.027 seconds

 

Post the discussion to improve the above solution.