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Computer Networking : A Top-Down Approach

Computer Networking : A Top-down Approach

Authors: James F. Kurose, Keith W. Ross
ISBN: 9780132856201
Edition: 6
Chapter: Transport Layer
Exercise: Problems
Question: 15



Consider the cross-country example shown in Figure 3.17. How big would the window size have to be for the channel utilization to be greater than 98 percent? Suppose that the size of a packet is 1,500 bytes, including both header fields and data.


Consider two systems A and B.


The round-trip propagation delay between A and B (RTT) = 30 ms.


Transmission rate of the link between A and B (R) = 1Gbps = 109bps.


The size of the data packet (L)= 1500 bytes (1500x8 bits)


The following is the formula to calculate the time required to transmit the packet over the 1 Gbps link:



where Dtrans is the time required.


Calculate the window size such that the channel utilization is greater than 98%.


Therefore, to utilize 98% of the channel, the window size should be 2451 packets approximately.

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