Consider the previous problem, but suppose that D has the value
a. 1001010101.
b. 0101101010.
c. 1010100000.
a)
The value of D+r is 10010101010000 is taken by previous problem.
Consider the value, D=1001010101
Now dividing D+r with G the value of R is:
So, R value is 0000
b)
The value of D+r is 01011010100000 is taken by previous problem.
Consider the value, D=0101101010.
Now dividing D+r with G the value of R is:
So, R value is 1111
C)
The value of D+r is 10101000000000 is taken by previous problem.
Consider the value, D=1010100000
Now dividing D+r with G the value of R is:
So, R value is 1001