The Tradition of Sharing

Help your friends and juniors by posting answers to the questions that you know. Also post questions that are not available.

To start with, Sr2Jr’s first step is to reduce the expenses related to education. To achieve this goal Sr2Jr organized the textbook’s question and answers. Sr2Jr is community based and need your support to fill the question and answers. The question and answers posted will be available free of cost to all.

Computer Networking : A Top-Down Approach

Computer Networking : A Top-down Approach

Authors: James F. Kurose, Keith W. Ross Chapter: Multimedia Networking
ISBN: 9780132856201 Exercise: Review
Edition: 6 Question: 1



Reconstruct Table 7.1 for when Victor Video is watching a 4 Mbps video, Facebook Frank is looking at a new 100 Kbyte image every 20 seconds, and Martha Music is listening to 200 kbps audio stream.


Assume that 1kbyte is 8000bits.

So, 100kbytes is equal to (8000*100kbytes)/1kbytes = 800000bits  

The bit rate for 20secs is 800000bits  

The bit rate of Face book Frank is calculated by

Therefore, the bit rate = 800000bits/20sec



The bytes transferred in 67mins = 40kbps *67*60

                                               = 160800 kbps




The bit rate of Victor video is 4 Mbps.

The bytes transferred in 67mins =4Mbps *67 mins*60




The bit rate of Martha Music is 200 kbps

The bytes transferred in 67mins =200kbps *67 mins*60

                                               = 804000kbps

                                               = 100500kbytes




Bit rate

Bytes transferred in 67mins

Facebook Frank



Martha Music



Victor Video




1 0


Post the discussion to improve the above solution.