Question
Reconstruct Table 7.1 for when Victor Video is watching a 4 Mbps video, Facebook Frank is looking at a new 100 Kbyte image every 20 seconds, and Martha Music is listening to 200 kbps audio stream.
Answer
Assume that 1kbyte is 8000bits.
So, 100kbytes is equal to (8000*100kbytes)/1kbytes = 800000bits
The bit rate for 20secs is 800000bits
The bit rate of Face book Frank is calculated by
Therefore, the bit rate = 800000bits/20sec
=40000bps
=40kbps
The bytes transferred in 67mins = 40kbps *67*60
= 160800 kbps
=20100kbytes
=20.1Mbytes
The bit rate of Victor video is 4 Mbps.
The bytes transferred in 67mins =4Mbps *67 mins*60
=16080Mbps/8
=2010Mbps
=2Gbytes
The bit rate of Martha Music is 200 kbps
The bytes transferred in 67mins =200kbps *67 mins*60
= 804000kbps
= 100500kbytes
=100Mbytes
|
|
Bit rate |
Bytes transferred in 67mins |
|
Facebook Frank |
40kbps |
20.1Mbytes |
|
Martha Music |
200kbps |
100Mbytes |
|
Victor Video |
4Mbps |
2Gbytes |