SHARE
HELP

To start with, Sr2Jr’s first step is to reduce the expenses related to education. To achieve this goal Sr2Jr organized the textbook’s question and answers. Sr2Jr is community based and need your support to fill the question and answers. The question and answers posted will be available free of cost to all.

Authors:
James F. Kurose, Keith W. Ross
Chapter:
Multimedia Networking
Exercise:
Review
Question:1 | ISBN:9780132856201 | Edition: 6

### Question

Reconstruct Table 7.1 for when Victor Video is watching a 4 Mbps video, Facebook Frank is looking at a new 100 Kbyte image every 20 seconds, and Martha Music is listening to 200 kbps audio stream.

Assume that 1kbyte is 8000bits.

So, 100kbytes is equal to (8000*100kbytes)/1kbytes = 800000bits

The bit rate for 20secs is 800000bits

The bit rate of Face book Frank is calculated by

Therefore, the bit rate = 800000bits/20sec

=40000bps

=40kbps

The bytes transferred in 67mins = 40kbps *67*60

= 160800 kbps

=20100kbytes

=20.1Mbytes

The bit rate of Victor video is 4 Mbps.

The bytes transferred in 67mins =4Mbps *67 mins*60

=16080Mbps/8

=2010Mbps

=2Gbytes

The bit rate of Martha Music is 200 kbps

The bytes transferred in 67mins =200kbps *67 mins*60

= 804000kbps

= 100500kbytes

=100Mbytes

 Bit rate Bytes transferred in 67mins Facebook Frank 40kbps 20.1Mbytes Martha Music 200kbps 100Mbytes Victor Video 4Mbps 2Gbytes

### Discussions

Post the discussion to improve the above solution.