Computer Networking : A Top-Down Approach

Computer Networking : A Top-down Approach

Authors: James F. Kurose, Keith W. Ross
ISBN: 9780132856201
Edition: 6
Chapter: Multimedia Networking
Exercise: Review
Question: 1


Question by Anonymous on 02 Apr, 2016 at 08:38 AM

Reconstruct Table 7.1 for when Victor Video is watching a 4 Mbps video, Facebook Frank is looking at a new 100 Kbyte image every 20 seconds, and Martha Music is listening to 200 kbps audio stream.

Answer by Samuel on 06 Apr, 2016 at 05:31 AM

Assume that 1kbyte is 8000bits.

So, 100kbytes is equal to (8000*100kbytes)/1kbytes = 800000bits  

The bit rate for 20secs is 800000bits  

The bit rate of Face book Frank is calculated by

Therefore, the bit rate = 800000bits/20sec



The bytes transferred in 67mins = 40kbps *67*60

                                               = 160800 kbps




The bit rate of Victor video is 4 Mbps.

The bytes transferred in 67mins =4Mbps *67 mins*60




The bit rate of Martha Music is 200 kbps

The bytes transferred in 67mins =200kbps *67 mins*60

                                               = 804000kbps

                                               = 100500kbytes




Bit rate

Bytes transferred in 67mins

Facebook Frank



Martha Music



Victor Video




1 0


Post the discussion improve the above solution.