2. Construct a truth table for the following:
a)
Given expression:
Truth table:
x | y | z | xyz | |||
0 | 0 | 0 | 0 | 0 | 1 | 1 |
0 | 0 | 1 | 0 | 0 | 1 | 1 |
0 | 1 | 0 | 0 | 0 | 1 | 1 |
0 | 1 | 1 | 0 | 0 | 1 | 1 |
1 | 0 | 0 | 0 | 1 | 1 | 1 |
1 | 0 | 1 | 0 | 1 | 1 | 1 |
1 | 1 | 0 | 0 | 1 | 1 | 1 |
1 | 1 | 1 | 1 | 0 | 0 | 1 |
b)
Given expression:
Truth table:
x | y | z | x+y | x+z | (x+y)(x+z)(\bar{x}+z) | |
0 | 0 | 0 | 0 | 0 | 1 | 1 |
0 | 0 | 1 | 0 | 1 | 1 | 1 |
0 | 1 | 0 | 1 | 0 | 1 | 1 |
0 | 1 | 1 | 1 | 1 | 1 | 1 |
1 | 0 | 0 | 1 | 1 | 0 | 0 |
1 | 0 | 1 | 1 | 1 | 1 | 1 |
1 | 1 | 0 | 1 | 1 | 0 | 0 |
1 | 1 | 1 | 1 | 1 | 1 | 1 |
b) The truth table for the following Boolean expression is:
(x+y)(x+z)(x’+z)
x |
y |
z |
x’ |
x+y |
x+z |
x’+z |
(x+y)(x+z)(x’+z) |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
I got the different answer for the quetion b, please check
Post the discussion to improve the above solution.