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#
Authors:
Michael T. Goodrich, Roberto Tamassia, Michael H. Goldwasser
Chapter:
Java Primer
Exercise:
Exercises
Question:6 | ISBN:9781118771334 | Edition: 6

Question

Write a short Java method that takes an integer n and returns the sum of all the odd positive integers less than or equal to n.

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Answer

package java_problems_datastructures;

import java.util.Scanner;

public class SumOfOddNumbers {

	public static void main(String args[]) {

		// Take the input from the console
		Scanner scanner = new Scanner(System.in);
		System.out.println("enter the number \n");
		int number = scanner.nextInt();

		// create an array to store odd numbers

		int[] oddNumbers = new int[number / 2 + 1];
		scanner.close();

		// push those odd numbers into an array
		int i = 0;
		long sum = 0;
		for (int odd = 1; odd <= number; odd++) {
			if (odd % 2 == 1) {
				oddNumbers[i++] = odd;
			}

		}

		// Calucualating the sum of odds through a loop

		for (i = 0; i < oddNumbers.length; i++) {

			sum += oddNumbers[i];

		}

		// print the sum

		System.out.println("sum of all odd positive integers less than or equal to " + number + " is " + sum);

	}

}

 

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Discussions

turntalien

//method tht takes an integer and calculates sum of all integers tht are odd
public static int intOddSum(int n) {
    int i, sum = 0;
    for(i = 0; i<=n; i++) {
        if ((i%2) == 1){
            sum += i;
        }
    }
    return sum;
}
//driver method
public class multipleCheck {
    public static void main(String[] args) {
        System.out.println(intOddSum(5));
    }

Post the discussion to improve the above solution.