Question
What is the output of the following cout statements embedded in these if-else statements? You are to assume that these are embedded in a complete correct program. Explain your answer.
a. if(0)
cout << "0 is true";
else
cout << "0 is false";
cout << endl;
b. if(1)
cout << "1 is true";
else
cout << "1 is false";
cout << endl;
c. if(-1)
cout << "-1 is true";
else
cout << "-1 is false";
cout << endl;
Answer
a)
The output of the given code snippet for the statement if (0) will be:
0 is false
Explanation:
Since the condition if (0) evaluates to false (0 is considered false in C++), the code will execute the else block.
Hence, the output will be "0 is false".
b)
The output of the code snippet for the statement if (1) will be:
1 is true
Explanation:
In C++, any non-zero value is considered true. Since the condition if (1) evaluates to true, the code will execute the if block.
Therefore, the output will be "1 is true".
c)
The output of the code snippet for the statement if (-1) will be:
-1 is true
Explanation:
Similar to the previous case, any non-zero value is considered true in C++. Since the condition if (-1) evaluates to true, the code will execute the if block.
Hence, the output will be "-1 is true".
In all cases, the cout << endl; statement adds a new line after printing the message, resulting in each message appearing on a separate line in the output.