What is the problem (if any) with this code?
char a_string[20] = "How are you? ";
strcat(a_string, "Good, I hope.");
The code seems to be concatenating two strings using the strcat
function. However, there is a potential issue with the code related to the size of the destination string a_string
.
Let's break down the code:
char a_string[20] = "How are you? ";
Here, we declare a character array a_string
with a size of 20 and initialize it with the string "How are you? " (including the null terminator '\0').
strcat(a_string, "Good, I hope.");
The strcat
function is used to concatenate the string "Good, I hope." to the existing string a_string
. The strcat
function appends the source string to the end of the destination string.
The problem with this code is that the destination string a_string
has a fixed size of 20 characters, including the null terminator. After the first initialization, the length of a_string
is 14 (including the null terminator), leaving 6 characters of available space. However, the string "Good, I hope." is longer than 6 characters, so when strcat
tries to concatenate the second string to the destination, it will exceed the array's bounds, leading to undefined behavior.
To fix this issue, we need to ensure that the destination string has enough space to accommodate both the initial string and the concatenated string. One way to do this is to make sure the destination string has enough space to hold the concatenated result.
Correct code:
char a_string[40] = "How are you? ";
strcat(a_string, "Good, I hope.");