Authors:
Walter Savitch ,julia Lobur
Chapter:
Pointers And Dynamic Arrays
Exercise:
Self-test Exercises
Question:9 | ISBN:9780321531346 | Edition: 7
Question
Write a type definition for pointer variables that will be used to point to
dynamic arrays. The array elements are to be of type char. Call the type
CharArray.
Answer
#include <stdio.h>
#include <stdlib.h>
typedef char* CharArray;
int main() {
int size = 5;
CharArray arr = (CharArray)malloc(size * sizeof(char));
if (arr == NULL) {
printf("Failed to allocate memory for the array.\n");
return 1;
}
// Assign values to the dynamic array
arr[0] = 'H';
arr[1] = 'e';
arr[2] = 'l';
arr[3] = 'l';
arr[4] = 'o';
// Access and print the elements of the array
for (int i = 0; i < size; i++) {
printf("%c ", arr[i]);
}
printf("\n");
// Free the memory allocated for the array
free(arr);
return 0;
}
OUTPUT OF THE PROGRAM CODE:
H e l l o
NOTE:
In this example, we use the CharArray type to declare a pointer variable arr. We then dynamically allocate memory for an array of char elements using malloc. We can access and manipulate the elements of the array using the pointer arr. Finally, we free the allocated memory using free when we no longer need the array.