What is the exact number of bytes in a system that contains (a) 32K bytes, (b) 64M bytes,and (c) 6.4G bytes?
(a) 1K bytes = 1024(i.e,2¹⁰) bytes
32K bytes = 32*1024
= 32,768 bytes.
(b)1M bytes = 1,048,576(i.e,2²⁰) bytes
64M bytes= 64*1,048,576
= 67,108,864 bytes
(c) 1G bytes = 1,073,741,824(i.e,2³⁰)bytes
6.4G bytes= 6.4*1,073,741,824
= 6,871,947,673.6 bytes