The output of the program:

Commented program:

//Header section
#include <iostream>
using namespace std;
//Function prototype
void cheers(int n);

//main program
int main( )

{
    //Call the method
    cheers(3);
    return 0;
}
//Function "cheers" accept an integer parameter value of n
//and check the if-else condition to loop the parameter
//value and print result on screen
void cheers(int n)
{
    //IF parameter value is equal to 1, then print
    //'Hurry' or print 'Hip' then next recursion Call
    //cheers.
    //This loop ends the parameter value is equal to 1
    
    if (n == 1)
    {
        cout << "Hurray\n";
    }
    else
    {
        cout << "Hip ";
        cheers(n-1);
    }
}

Explanation:

Call the method, cheers with parameter value is 3 in main() function.
The following points are verify the cheers method:

• This method takes n value is 3 and verify the loop condition.
• Verify the "if" condtion is first, if n is not equal to 1, then go to
• "else" condtion. So, first print "Hip", then call, cheers(n-1)=cheers(3-1)=cheers(2).
• Now again if-else condition check to method cheers(2), it also go to print "Hip" again and then call, cheers(2-1)=cheers(1).
• Now, again verify the if-else condition, if n is equal to 1, then print "Hurray" and exit the loop.

Finaly, display the output is: Hip Hip Hurray