Consider a modification to TCP’s congestion control algorithm. Instead of additive increase, we can use multiplicative increase. A TCP sender increases its window size by a small positive constant a (0 < a < 1) whenever it receives a valid ACK. Find the functional relationship between loss rate L and maximum congestion window W. Argue that for this modified TCP, regardless of TCP’s average throughput, a TCP connection always spends the same amount of time to increase its congestion window size from W/2 to W.
The maximum window size is represented by w.
The total number of segments(S) sent out during the interval when TCP changes its window size from w/2 up to and includes w.
S=w/2 +(w/2)*(1+a)+(w/2)*(1+a)^2 +(w/2)*(1+a)^3 +(w/2)*(1+a)^4 + . . .+ (w/2)*(1+a)^n
Here,n=log(1+a) 2,then S=w*(2a+1)/(2a).
The Loss rate is derived by
L=1/S= (2a)/ (w*(2a+1)).
The TCP takes time to increase its window size from w/2 to w is calculated by
n*RTT = (log(1+a) 2 * RTT
This is independent of TCP’s average throughput.
TCP’s average throughput is derived by
Throughput B=MSS*S/((n+1)*RTT) =MSS/(L*(k+1)*RTT)
Note that the derived throughput is different from original throughput.