SHARE
SPREAD
HELP

The Tradition of Sharing

Help your friends and juniors by posting answers to the questions that you know. Also post questions that are not available.


To start with, Sr2Jr’s first step is to reduce the expenses related to education. To achieve this goal Sr2Jr organized the textbook’s question and answers. Sr2Jr is community based and need your support to fill the question and answers. The question and answers posted will be available free of cost to all.

 

#
Authors:
James F. Kurose, Keith W. Ross
Chapter:
Multimedia Networking
Exercise:
Problems
Question:8 | ISBN:9780132856201 | Edition: 6

Question

Repeat Parts a and b in Question P7 for the estimate of average delay deviation.

TextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbookTextbook

Answer

Refer the previous question 7( sub parts a and b):

a)

 

To express the estimate of delay d in terms of the four sample delays, we can use the formula described in Section 7.3:

d=(1-u)*d+u*(r-t)

Using this formula for each sample delay, we have:

\large d = (1 - u) * ((1 - u) * ((1 - u) * d + u * (r4 - t4)) + u * (r3 - t3)) + u * (r2 - t2) + u * (r1 - t1)

 

b)

To generalize the formula for n sample delays, we can use a recursive approach:

\large d = (1 - u) * d + u * (r - t)

Expanding this formula for n sample delays, we have:

\large d = (1 - u)^{n} * d + u * (1 - (1 - u)^{n}) / u * (r1 - t1) + u * (1 - (1 - u)^{n}) / u * (r2 - t2) + ... + u * (1 - (1 - u)^{n}) / u * (rn - tn)

Simplifying further, we can express the general formula as:

\large d = (1 - u)^{n} * d + (1 - (1 - u)^{n}) / u * ((r1 - t1) + (r2 - t2) + ... + (rn - tn))

d = (1 - u)^n * d + (1 - (1 - u)^n) / u * ((r1 - t1) + (r2 - t2) + ... + (rn - tn))

This formula provides the estimate of average delay deviation based on n sample delays.

0 0

Discussions

Post the discussion to improve the above solution.